In an AM wave,the carrier power is given by: | vedclass

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(C) The carrier wave is represented as $e_c(t) = E_c \sin(\omega_c t)$,where $E_c$ is the peak amplitude of the carrier wave.Power is defined as the m

Vedclass · Accepted Answer

$P_c = \frac{E_c^2}{2R}$

Vedclass · Answer

(C) The carrier wave is represented as $e_c(t) = E_c \sin(\omega_c t)$,where $E_c$ is the peak amplitude of the carrier wave.Power is defined as the mean square voltage divided by resistance: $P_c = \frac{V_{rms}^2}{R}$.Since the root mean square $(RMS)$ value of a sinusoidal wave is $E_{rms} = \frac{E_c}{\sqrt{2}}$,the power is calculated as:$P_c = \frac{(E_c / \sqrt{2})^2}{R} = \frac{E_c^2}{2R}$.

In an $AM$ wave,the carrier power is given by:

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